Problem Statement:
A professional cyclist is cycling at 13 m/s in a race.
Solution:
(a) If rolling resistance is ignored, the force supplied by the cyclist is used to overcome drag alone and these two forces balance. Thus, the power expended can be computed as
Using the CD and A values from the drag coefficient table we have
That is about 0.56 hp. Note we have converted 3.9 ft2 to 0.362 m2 for A (1 ft = 0.3048 m).
(b) If it is the same cyclist, we can assume the power output is the same as in part (a), but now the drag coefficient and cross-sectional area are different. From the drag coefficient table we find CD = 0.12 and A = 5.0 ft2 = 0.465 m2. Using the relationship between and V0 from part (a) we have
which is about 52 mph.